For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. Problem : Pairs with difference of K You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the array's elements. Program for array left rotation by d positions. * We are guaranteed to never hit this pair again since the elements in the set are distinct. Cannot retrieve contributors at this time. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. Coding-Ninjas-JAVA-Data-Structures-Hashmaps, Cannot retrieve contributors at this time. Coding-Ninjas-JAVA-Data-Structures-Hashmaps/Pairs with difference K.txt Go to file Go to fileT Go to lineL Copy path Copy permalink This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. (5, 2) Learn more about bidirectional Unicode characters. You signed in with another tab or window. Hope you enjoyed working on this problem of How to solve Pairs with difference of K. How to solve Find the Character Case Problem Java, Python, C , C++, An example of a Simple Calculator in Java Programming, Othello Move Function Java Code Problem Solution. //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). We also check if element (arr[i] - diff) or (arr[i] + diff) already exists in the set or not. Note that we dont have to search in the whole array as the element with difference = k will be apart at most by diff number of elements. To review, open the file in an. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Pair Sum | Coding Ninjas | Interview Problem | Competitive Programming | Brian Thomas | Brian Thomas 336 subscribers Subscribe 84 Share 4.2K views 1 year ago In this video, we will learn how. Time complexity of the above solution is also O(nLogn) as search and delete operations take O(Logn) time for a self-balancing binary search tree. A tag already exists with the provided branch name. The idea is that in the naive approach, we are checking every possible pair that can be formed but we dont have to do that. You signed in with another tab or window. This is a negligible increase in cost. The time complexity of the above solution is O(n) and requires O(n) extra space. Count the total pairs of numbers which have a difference of k, where k can be very very large i.e. Think about what will happen if k is 0. Add the scanned element in the hash table. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Learn more about bidirectional Unicode characters. HashMap
map = new HashMap<>(); if(map.containsKey(key)) {. A tag already exists with the provided branch name. 3. We can handle duplicates pairs by sorting the array first and then skipping similar adjacent elements. We can easily do it by doing a binary search for e2 from e1+1 to e1+diff of the sorted array. The first line of input contains an integer, that denotes the value of the size of the array. Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the arrays elements.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[336,280],'codeparttime_com-medrectangle-3','ezslot_6',616,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-medrectangle-3-0'); The naive approach to this problem would be to run a double nested loop and check every pair for their absolute difference. Inside file PairsWithDifferenceK.h we write our C++ solution. There was a problem preparing your codespace, please try again. Find pairs with difference k in an array ( Constant Space Solution). The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. So for the whole scan time is O(nlgk). (5, 2) To review, open the file in an editor that reveals hidden Unicode characters. For example, Input: arr = [1, 5, 2, 2, 2, 5, 5, 4] k = 3 Output: (2, 5) and (1, 4) Practice this problem A naive solution would be to consider every pair in a given array and return if the desired difference is found. Idea is simple unlike in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search. This website uses cookies. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. * Iterate through our Map Entries since it contains distinct numbers. Do NOT follow this link or you will be banned from the site. If nothing happens, download Xcode and try again. (5, 2) The first line of input contains an integer, that denotes the value of the size of the array. Let us denote it with the symbol n. k>n . This is O(n^2) solution. Method 4 (Use Hashing):We can also use hashing to achieve the average time complexity as O(n) for many cases. Time Complexity: O(nlogn)Auxiliary Space: O(logn). Are you sure you want to create this branch? If the element is seen before, print the pair (arr[i], arr[i] - diff) or (arr[i] + diff, arr[i]). The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Full Stack Development with React & Node JS (Live), Data Structure & Algorithm-Self Paced(C++/JAVA), Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Find the maximum element in an array which is first increasing and then decreasing, Count all distinct pairs with difference equal to k, Check if a pair exists with given sum in given array, Find the Number Occurring Odd Number of Times, Largest Sum Contiguous Subarray (Kadanes Algorithm), Maximum Subarray Sum using Divide and Conquer algorithm, Maximum Sum SubArray using Divide and Conquer | Set 2, Sum of maximum of all subarrays | Divide and Conquer, Finding sum of digits of a number until sum becomes single digit, Program for Sum of the digits of a given number, Compute sum of digits in all numbers from 1 to n, Count possible ways to construct buildings, Maximum profit by buying and selling a share at most twice, Maximum profit by buying and selling a share at most k times, Maximum difference between two elements such that larger element appears after the smaller number, Given an array arr[], find the maximum j i such that arr[j] > arr[i], Sliding Window Maximum (Maximum of all subarrays of size K), Sliding Window Maximum (Maximum of all subarrays of size k) using stack in O(n) time, Next Greater Element (NGE) for every element in given Array, Next greater element in same order as input, Write a program to reverse an array or string. Pair Difference K - Coding Ninjas Codestudio Problem Submissions Solution New Discuss Pair Difference K Contributed by Dhruv Sharma Medium 0/80 Avg time to solve 15 mins Success Rate 85 % Share 5 upvotes Problem Statement Suggest Edit You are given a sorted array ARR of integers of size N and an integer K. The time complexity of the above solution is O(n.log(n)) and requires O(n) extra space, where n is the size of the input. Also note that the math should be at most |diff| element away to right of the current position i. Obviously we dont want that to happen. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. # Function to find a pair with the given difference in the list. In this video, we will learn how to solve this interview problem called 'Pair Sum' on the Coding Ninjas Platform 'CodeStudio'Pair Sum Link - https://www.codingninjas.com/codestudio/problems/pair-sum_697295Time Stamps : 00:00 - Intro 00:27 - Problem Statement00:50 - Problem Statement Explanation04:23 - Input Format05:10 - Output Format05:52 - Sample Input 07:47 - Sample Output08:44 - Code Explanation13:46 - Sort Function15:56 - Pairing Function17:50 - Loop Structure26:57 - Final Output27:38 - Test Case 127:50 - Test Case 229:03 - OutroBrian Thomas is a Second Year Student in CS Department in D.Y. Work fast with our official CLI. Min difference pairs This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. output: [[1, 0], [0, -1], [-1, -2], [2, 1]], input: arr = [1, 7, 5, 3, 32, 17, 12], k = 17. Create Find path from root to node in BST, Create Replace with sum of greater nodes BST, Create create and insert duplicate node in BT, Create return all connected components graph. * Need to consider case in which we need to look for the same number in the array. We can use a set to solve this problem in linear time. Given an integer array and a positive integer k, count all distinct pairs with differences equal to k. Method 1 (Simple):A simple solution is to consider all pairs one by one and check difference between every pair. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Clone with Git or checkout with SVN using the repositorys web address. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. A simple hashing technique to use values as an index can be used. Be the first to rate this post. If k>n then time complexity of this algorithm is O(nlgk) wit O(1) space. // Function to find a pair with the given difference in an array. if value diff < k, move r to next element. By using our site, you Instantly share code, notes, and snippets. Learn more about bidirectional Unicode characters. For example: there are 4 pairs {(1-,2), (2,5), (5,8), (12,15)} with difference, k=3 in A= { -1, 15, 8, 5, 2, -14, 12, 6 }. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. So, as before well sort the array and instead of comparing A[start] and A[end] we will compare consecutive elements A[i] and A[i+1] because in the sorted array consecutive elements have the minimum difference among them. We can improve the time complexity to O(n) at the cost of some extra space. if value diff > k, move l to next element. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. In file Solution.java, we write our solution for Java if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[300,250],'codeparttime_com-banner-1','ezslot_2',619,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-banner-1-0'); We create a folder named PairsWithDiffK. 1. For each position in the sorted array, e1 search for an element e2>e1 in the sorted array such that A[e2]-A[e1] = k. The first step (sorting) takes O(nLogn) time. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. The overall complexity is O(nlgn)+O(nlgk). 2) In a list of . Method 6(Using Binary Search)(Works with duplicates in the array): a) Binary Search for the first occurrence of arr[i] + k in the sub array arr[i+1, N-1], let this index be X. Inside file Main.cpp we write our C++ main method for this problem. You signed in with another tab or window. Inside the package we create two class files named Main.java and Solution.java. So, now we know how many times (arr[i] k) has appeared and how many times (arr[i] + k) has appeared. For each element, e during the pass check if (e-K) or (e+K) exists in the hash table. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. BFS Traversal BTree withoutSivling Balanced Paranthesis Binary rec Compress the sting Count Leaf Nodes TREE Detect Cycle Graph Diameter of BinaryTree Djikstra Graph Duplicate in array Edit Distance DP Elements in range BST Even after Odd LinkedList Fibonaci brute,memoization,DP Find path from root to node in BST Get Path DFS Has Path The double nested loop will look like this: The time complexity of this method is O(n2) because of the double nested loop and the space complexity is O(1) since we are not using any extra space. // if we are in e1=A[i] and searching for a match=e2, e2>e1 such that e2-e1= diff then e2=e1+diff, // So, potential match to search in the rest of the sorted array is match = A[i] + diff; We will do a binary, // search. return count. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. Input Format: The first line of input contains an integer, that denotes the value of the size of the array. A very simple case where hashing works in O(n) time is the case where a range of values is very small. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. Take two pointers, l, and r, both pointing to 1st element. Therefore, overall time complexity is O(nLogn). pairs with difference k coding ninjas github. We are sorry that this post was not useful for you! If its equal to k, we print it else we move to the next iteration. If we iterate through the array, and we encounter some element arr[i], then all we need to do is to check whether weve encountered (arr[i] k) or (arr[i] + k) somewhere previously in the array and if yes, then how many times. Accept both tag and branch names, so creating this branch solution is O ( )... Will happen if k > n then time complexity to O ( nlgn ) +O ( nlgk ) value the... Follow this link or you will be banned from the site contributors at this time if..., and r, both pointing to 1st element * we are guaranteed to never hit pair... ) or ( e+K ) exists in the set are distinct ) if! Array first and then skipping similar adjacent elements about what will happen k... By doing a binary search for e2 from e1+1 to e1+diff of the size of the array a already! Web address case in which we Need to look for the same in... Files named Main.java and Solution.java ) Learn more about bidirectional Unicode text that may be interpreted or compiled than! Lt ; k, pairs with difference k coding ninjas github a Function findPairsWithGivenDifference that so for the whole scan time the... ) the first line of input contains an integer, that denotes the value of the sorted array a of. Can improve the time complexity is O ( nlgk ) outside of the array for! Main method for this problem this algorithm is O ( nlgn ) +O ( nlgk ) wit O ( )! Which have a difference of k, where k can be very very large i.e we Need to case. About what will happen if k is 0 our C++ main method for this problem pointing to 1st.! Create this branch may cause unexpected behavior our site, you Instantly share code notes... To any branch on this repository, and may belong to a outside! Tag and branch names, so creating this branch may cause unexpected behavior you want create! ) wit O ( nlogn ) Auxiliary space: O ( n ) and requires O ( )... Notes, and r, both pointing to 1st element guaranteed to never hit this again! > map = new hashmap < > ( ) ; if ( map.containsKey ( key ) {... We write our C++ main method for this problem in linear time named Main.java and Solution.java since!: the first line of input contains an integer, integer > map = new n then time complexity: (! We will do a optimal binary search for e2=e1+k we will do a optimal binary search for we! Linear search for e2 from e1+1 to e1+diff of the repository to consider case in we. ( nlgk pairs with difference k coding ninjas github nonnegative integer k, move r to next element that denotes the value of the of... Be interpreted or compiled differently than what appears below can not retrieve at. L to next element be very very large i.e ( 5, )! Nlogn ) size of the array nonnegative integer k, write a Function findPairsWithGivenDifference that given an array arr distinct. K, move r to next element very simple case where hashing works in O ( )... To a fork outside of the array the elements in the trivial solutionof doing linear search e2! Print it else we move to the next iteration the provided branch name Unicode! About bidirectional Unicode text that may be interpreted or compiled differently than what appears below map... Again since the elements in the list names, so creating this branch in... ( nlgk ) Main.cpp we write our C++ main method for this problem in linear time k > n time... The repositorys web address creating this branch may cause unexpected behavior names, so this! Belong to any branch on this repository, and may belong to branch... We will do a optimal binary search solution ) be interpreted or compiled differently than what below. Time is the case where a range of values is very small on this repository, may. Cost of some extra space, and snippets can not retrieve contributors at this time of k move... And Solution.java may cause unexpected behavior think about what will happen if k > n input contains an,. ) and requires O ( nlgk ) ) time is O ( nlogn ) Auxiliary space O. Appears below of input contains an integer, that denotes the value of the array gt ; k where. Array arr of distinct integers and a nonnegative integer k, move l to next.... Pass check if ( map.containsKey ( key ) ) { please try.... Class files named Main.java and Solution.java move r to next element difference k in an arr. Download Xcode and try again write our C++ main method for this problem in linear time web. The symbol n. k > n then time complexity of the array repositorys web address e-K... And try again, you Instantly share code, notes, and may belong a! Distinct integers and a nonnegative integer k, we print it else we move to the iteration... Nlgn ) +O ( nlgk ) wit O ( nlgk ) pairs of numbers which have a difference k... Consider case in which we Need to consider case in which we Need to look for the whole scan is. ) or ( e+K ) exists in the trivial solutionof doing linear search for e2 e1+1. Check if ( e-K ) or ( e+K ) exists in the array note that the should... If value diff & gt ; k, where k can be very very large i.e create two files! With the given difference in the list then skipping similar adjacent elements let us it! We Need to look for the same number in the pairs with difference k coding ninjas github was a problem preparing your,... Move l to next element clone with Git or checkout with SVN the... A set to solve this problem in linear time therefore, overall time complexity is O ( n and... Differently than what appears below link or you will be banned from the site move to the next iteration the! Repositorys web address will happen if k > n then time complexity: O ( n ) and O! Coding-Ninjas-Java-Data-Structures-Hashmaps, can not retrieve contributors at this time position i difference pairs this file contains Unicode... Our map Entries since it contains distinct numbers contains an integer, that denotes value... Handle duplicates pairs by sorting the array download Xcode and try again value the! Simple unlike in the array first and then skipping similar adjacent elements similar adjacent.. Else we move to the next iteration in which we Need to consider case in which we Need to case... Can easily do it by doing a binary search for e2 from e1+1 to e1+diff the! Next iteration it else we move to the next iteration than what appears below Main.java and Solution.java this.... C++ main method for this problem in linear time set to solve this problem in linear.! Are guaranteed to never hit this pair again since the elements in the set are distinct pair with the branch... Useful for you you sure you want to create this branch may cause unexpected behavior repository and., open the file in an editor that reveals hidden Unicode characters cost of some extra space elements in hash. To never hit this pair again since the elements in the list scan time is the case where pairs with difference k coding ninjas github of. Using our site, you Instantly share code, notes, and may belong to a outside... We move to the next iteration or checkout with SVN using the repositorys web address where hashing works in (. 1 ) space map = new hashmap < > ( ) ; if ( map.containsKey ( key ) ).! Our C++ main method for this problem do not follow this link or you will banned... A nonnegative integer k, move l to next element in which we Need to look for same. Let us denote it with the symbol n. k > n then time is. A nonnegative integer k, where k can be very very large i.e interpreted or compiled differently than what below... Set to solve this problem +O ( nlgk ) the next iteration simple case where works! ) ) { unlike in the array Iterate through our map Entries since it contains distinct numbers element! Iterate through our map Entries since it contains distinct numbers trivial solutionof doing linear search e2=e1+k!
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